Answer:
Time taken, [tex]t=9.18\times 10^{-10}\ s[/tex]
Explanation:
Given that,
Initial speed of the electron, [tex]u=4.04\times 10^5\ m/s[/tex]
Acceleration of the electron, [tex]a=3.3\times 10^{14}\ m/s^2[/tex]
Final speed of the electron, [tex]v=7.07\times 10^5\ m/s[/tex]
We need to find the time taken by the electron to reach its final speed. It can be calculated using first equation of motion as :
[tex]t=\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{7.07\times 10^5-4.04\times 10^5}{3.3\times 10^{14}}[/tex]
[tex]t=9.18\times 10^{-10}\ s[/tex]
So, the time to reach its final speed is [tex]9.18\times 10^{-10}\ s[/tex]. Hence, this is the required solution.
