Answer:
[tex]5.\, F=\frac{9C}{5}+32\\6.\,y=\frac{c-ax}{b}\\7.\,p=\frac{mq}{n}\\8.\,t=\frac{A-P}{Pr}\\9.\,y=\frac{12-6x}{5}\\10.\,y=\frac{9x-6}{3}\\12. x=\frac{9+5y}{6}\\13.\,\pi=\frac{c}{d}\\14.\,A=\frac{s^2}{R}\\15.\,w=\frac{P-2l}{2}\\16.\,y=\frac{3x-2}{5}\\17.,x=\frac{6-3by}{2a}\\18.\,w=\frac{V}{lh}[/tex]
Step-by-step explanation:
We need to solve following equations in terms of indicated variable:
[tex]5.C=\frac{5}{9}\left ( F-32 \right ):F\\6.ax+by=c;y\\7.\frac{m}{n}=\frac{p}{q};p\\8.A=P+Prt;t\\9.6x+5y=12;y\\10.3y+2=9x-4;y\\12.6x-5y=9;x\\13.C=\pi d\\14.R=\frac{s^2}{A};A\\15.P=2l+2w;w\\16.3x-5y=2;y\\17.2ax+3by=6;x\\18.V=lwh;w[/tex]
Solution:
[tex]5.\, F=\frac{9C}{5}+32\\6.\,y=\frac{c-ax}{b}\\7.\,p=\frac{mq}{n}\\8.\,t=\frac{A-P}{Pr}\\9.\,y=\frac{12-6x}{5}\\10.\,y=\frac{9x-6}{3}\\12. x=\frac{9+5y}{6}\\13.\,\pi=\frac{c}{d}\\14.\,A=\frac{s^2}{R}\\15.\,w=\frac{P-2l}{2}\\16.\,y=\frac{3x-2}{5}\\17.,x=\frac{6-3by}{2a}\\18.\,w=\frac{V}{lh}[/tex]
