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A particle starts from the origin at t = 0 with an initial velocity having an x component of 29.8 m/s and a y component of −18 m/s. The particle moves in the xy plane with an x component of acceleration only, given by 5.21 m/s 2 . Determine the x component of velocity after 7.22 s. Answer in units of m/s.

Respuesta :

Lucianorayos1

Answer:

Vx(7,22s)=67,42m/s

Explanation:

V(t)=Vo+a(t) [tex]Vx(7,22s)=Vxo+5,21\frac{m}{s^{2} } *7,22s

Vx(7,22s)=29,8m/s +37,62m/s=67,42m/s[/tex]

you just consider the x component of your velocity, then you apply the Velocity formula of uniform accelerated rectilinear motion, and you get to the result, by replacing t (time) by the value given 7,22s.

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