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Metal sphere A has a charge of -Q. An identical metal sphere B has a charge of 2Q. The magnitude of the electric force on B due to A is F. The magnitude of the electric force on A due to B must be(A) 2F(B) F/4(C) F/2(D) F(E) 4F

Respuesta :

Answer:

option D ) is correct.

Explanation:

When two charges Q₁ and Q₂ which are unequal in magnitude as well as in nature are at a distance of R then a force F is created between them which is given by the expression

 F = k ( Q₁ X Q₂) / R²

This force acts equally on both the charges Q₁ and Q₂ irrespective of the fact that they are unequal charges . In other words both Q₁ and Q₂ experience same force F whose value is given above.

In the given case too charges are unequal in magnitude and in nature . They will attract each other with equal force . So if A experiences force F , B too will experience the same force,

Hence option D ) is correct.

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