Answer:
The probability of choosing exactly 2 male and 4 female students =[tex]\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}[/tex]
Step-by-step explanation:
We are given that a class has 35 students
Number of male=16
Number of female=19
We have to choose 6 students for committee
We have to find the probability that exactly 2 male students are selected
Probability=P(E)=[tex]\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}[/tex]
If we have to choose total 6 student in which 2 male and 4 female
Combination formula:
[tex]nC_r=\frac{n!}{r!(n-r)!}[/tex]
Using the formula
The probability of choosing exactly 2 male and 4 female students =[tex]\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}[/tex]
