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A survey plat depicted to the right shows two lots that form a trapezoid. The measures of the parallel sides are 50.29 ft and 91.61 ft. The height of the trapezoid is 51.83 ft. Find the combined area of the two lots.

Respuesta :

calculista

Answer:

The combined area of the two lots is [tex]3,677.34\ ft^2[/tex]

Step-by-step explanation:

we know that

The area of a trapezoid is equal to

[tex]A=\frac{1}{2}(b_1+b_2)h[/tex]

where

b_1 and b_2 are the parallel sides

h is the height of trapezoid

In this problem we have

[tex]b_1=50.29\ ft\\b_2=91.61\ ft\\h=51.83\ ft[/tex]

substitute in the formula

[tex]A=\frac{1}{2}(50.29+91.61)51.83[/tex]

[tex]A=\frac{1}{2}(141.9)51.83[/tex]

[tex]A=3,677.34\ ft^2[/tex]

Nonicorp1

Answer:

3677.3385ft²

Step-by-step explanation:

The area of a trapezium=1/2(b+l)×Height

where;

b and l are parallel sides

b=the length of one parallel side, the shorter one=50.29 ft

l=the length of the other parallel side, the longer one=91.62 ft

h=is the perpendicular height to b

Replacing;

Area=1/2(50.29+91.61)×51.83=3677.3385ft²

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