Answer:
Option A.
Step-by-step explanation:
The vertex form of a parabola is
[tex]y=a(x-h)^2+k[/tex]
where, (h,k) is vertex and a is a constant.
The vertex of the parabola is (-2,-1).
Substitute h=-2 and k=-1 in the above equation.
[tex]y=a(x-(-2))^2+(-1)[/tex]
[tex]y=a(x+2)^2-1[/tex] .... (1)
The parabola passes through the point (0,3). So, it must be satisfy by the point (0,3).
[tex]3=a(0+2)^2-1[/tex]
[tex]3+1=4a[/tex]
[tex]a=1[/tex]
Substiturte a=1 in equation (1).
[tex]y=1(x+2)^2-1[/tex]
On simplification we get
[tex]y=x^2+4x+4-1[/tex]
[tex]y=x^2+4x+3[/tex]
It means the equation [tex]x^2+4x+3=0[/tex] could be solved using the given graph.
Therefore, the correct option is A.
