Answer:
Part 1) The perimeter of the park is [tex]P=52\ yd[/tex]
Part 2) The area of the park is [tex]A=137\ yd^2[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
Part 1) Find the perimeter pf the park
we know that
The perimeter of the figure is the sum of its six length sides (see the figure)
so
[tex]P=17+5+4+4+(17-4)+9\\P=52\ yd[/tex]
Part 2) Find the area of the park
The area of the park is equal to the area of two rectangles
The area of rectangle is equal to
[tex]A=bh[/tex]
substitute the values
[tex]A=13(9)+4(5)[/tex]
[tex]A=117+20[/tex]
[tex]A=137\ yd^2[/tex]