Answer:
Part a) The new rectangle labeled in the attached figure N 2
Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is [tex]x^{2} +11x+28[/tex]
Part c) The area of the second rectangle is 54 in^2
Part d) see the explanation
Step-by-step explanation:
The complete question in the attached figure N 1
Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above
we know that
The dimensions of the new rectangle will be
[tex]Length=(x+4)\ in[/tex]
[tex]width=(x+7)\ in[/tex]
The diagram of the new rectangle in the attached figure N 2
Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial
The diagram of the new rectangle with their areas in the attached figure N 3
we have that
To find out the area of each portion, multiply its length by its width
[tex]A1=(x)(x)=x^{2}\ in^2[/tex]
[tex]A2=(4)(x)=4x\ in^2[/tex]
[tex]A3=(x)(7)=7x\ in^2[/tex]
[tex]A4=(4)(7)=28\ in^2[/tex]
The total area of the second rectangle is the sum of the four areas
[tex]A=A1+A2+A3+A4[/tex]
State the product of (x+4) and (x+7) as a trinomial
[tex](x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28[/tex]
Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?
we know that
The area of the second rectangle is equal to
[tex]A=A1+A2+A3+A4[/tex]
For x=2 in
substitute the value of x in the area of each portion
[tex]A1=(2)(2)=4\ in^2[/tex]
[tex]A2=(4)(2)=8\ in^2[/tex]
[tex]A3=(2)(7)=14\ in^2[/tex]
[tex]A4=(4)(7)=28\ in^2[/tex]
[tex]A=4+8+14+28[/tex]
[tex]A=54\ in^2[/tex]
Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in
We have that
The trinomial is
[tex]A(x)=x^{2} +11x+28[/tex]
For x=2 in
substitute and solve for A(x)
[tex]A(2)=2^{2} +11(2)+28[/tex]
[tex]A(2)=4 +22+28[/tex]
[tex]A(2)=54\ in^2[/tex] ----> verified
therefore
The trinomial represent the total area of the second rectangle
