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Small rockets are used to make tiny corrections to the speed of a satellite. If a rocket has a thrust of
35 N and is used to change the velocity of a 72000-kg satellite by 63 cm/s, for how long should it be
fired?
Variables:
Equations:
Answers

Respuesta :

The rocket should be fired for 129600 seconds.

Why?

We can calculate for how long should the rocket be fired by using the following equation:

[tex]Force=mass*aacceleration=mass*\frac{v-v_{o}}{time} \\\\time=\frac{mass*(v-v_{o})}{Force}[/tex]

From the statement we know:

- Initial speed equal to zero.

- Force equal to 272N.

- Final speed (for the moment) equal to 62 m/s.

- Mass equal to 72000 Kg.

So, substituting and calculating, we have:

[tex]time=\frac{mass*(v-v_{o})}{Force}[/tex]

[tex]time=\frac{mass*(v-v_{o})}{Force}\\\\time=\frac{72000*(63\frac{m}{s} -0)}{35\frac{Kg.m}{s^{2}}}=129600s[/tex]

Hence, we have:

Variables: Time

Equations:

[tex]Force=mass*aacceleration=mass*\frac{v-v_{o}}{time} \\\\time=\frac{mass*(v-v_{o})}{Force}[/tex]

Answers: The rocket should be fired for 129600 seconds.

Have a nice day!