Answer:
$3355
Step-by-step explanation:
Since the job offers starting salary of $2200 and monthly raise of $105 during his first year of training.
∴ a = 2200 and d = 105
Since the general form of A.P is,
a, a + d, a + 2d, a + 3d, .............[tex]a_{n}[/tex]
Where, [tex]a_{n}[/tex] is the last term of A.P or his monthly salary at the end of his training and n is the number of terms in a series.
So, the A.P is:
2200, 2200 + 105, 2200 + 2(105) .........[tex]a_{n}[/tex]
2200, 2305, 2410 ............[tex]a_{n}[/tex]
Since there is 12 month in a year therefore, n = 12.
[tex]a_{n} = a + (n - 1) d\\[/tex]
.[tex]a_{n}[/tex] = 2200 + ( 12 - 1) × 105
= 2200 + 11 × 105
= 2200 + 1155
= 3355
∴ .[tex]a_{n}[/tex] = 3355
So the monthly salary of Jose at the end of his training is 3355$.
