Respuesta :
Answer:
Package strikes ground 278m from where it was released.
Horizontal component of velocity is still 48m/s.
Explanation:
To figure out the horizontal distance travelled (the range), we need to know how long the package was traveling through the air. To figure that out, we use the vertical information:
Given the following vertical information:
d = 165
a = 9.8
vi = 0
t = ?
[tex]d=v_it+0.5at^2\\165=0+0.5(9.8)t^2\\165=4.9t^2\\t^2=33.7\\t=5.8[/tex]
We know the package was airborne for 5.8 seconds. Now we use that when considering all the horizontal stuff. Given:
t = 5.8
v = 48
d = ?
[tex]v = \frac{d}{t}\\48= \frac{d}{5.8}\\d = 278[/tex]
The horizontal component of the velocity is always the same because there are no horizontal forces acting on the package (assuming we're ignoring drag here).
