Answer:
The temperature of the gas will be 460 K at 276 Kpa if a gas at a temperature of 300 K and a pressure of 180 Kpa.
Explanation:
According to Gay-Lussac's Law, at constant volume the pressure is directly proportional to temperature. Let us consider P1 and T1 are the initial pressure and temperature of a gas. P2 and T2 are the final pressure and temperature of a gas.
This is represented as [tex]\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}[/tex] . Given that P1 = 180Kpa T1 = 300 K P2 = 276 Kpa and T2 = ? now substitute in the above formula [tex]\frac{180}{300}=\frac{276}{T_{2}}[/tex] [tex]T_{2}=\frac{276 \times 300}{180}=460 \mathrm{K}[/tex]
Hence the temperature 460K for given questions.
