contestada

A triangle has vertices at B(-3,0), C(2, -1), D(-1,2). Which transformation would produce an image with vertices B"(-2, 1), C"(3, 2), D"(0, -1)?
(x, y) - (x,-y), (x, y) - (x + 1, y + 1)
O(x, y) -- (-x,y),(x, y) - (x + 1, y + 1)
(x, y) - (x, -y), (x, y) - (x + 2 y + 2)
O(x, y) - (-x,y),(x,y) - (x + 2, Y + 2)

Respuesta :

frika

Answer:

1st option

[tex](x,y)\rightarrow (x,-y)[/tex]

[tex](x,y)\rightarrow (x+1,y+1)[/tex]

Step-by-step explanation:

A triangle has vertices at B(-3,0), C(2, -1), D(-1,2).

1. Reflect this triangle across the x-axis according to the rule

[tex](x,y)\rightarrow (x,-y)[/tex]

Then

  • [tex]B(-3,0)\rightarrow B'(-3,0);[/tex]
  • [tex]C(2,-1)\rightarrow C'(2,1);[/tex]
  • [tex]D(-1,2)\rightarrow D'(-1,-2).[/tex]

2. Translate triangle B'C'D' 1 unit to the right and 1 unit up according to the rule

[tex](x,y)\rightarrow (x+1,y+1)[/tex]

Then

  • [tex]B'(-3,0)\rightarrow B''(-2,1);[/tex]
  • [tex]C'(2,1)\rightarrow C''(3,2);[/tex]
  • [tex]D'(-1,-2)\rightarrow D''(0,-1).[/tex]
Ver imagen frika

Otras preguntas