Answer:
< 5, - 23 >
Step-by-step explanation:
The vertex of f(x) = x² is at the origin (0, 0)
Find the vertex of g(x) = x² - 10x + 2
Given a quadratic in standard form : ax² + bx + c : a ≠ 0
The the x- coordinate of the vertex is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
g(x) = x² - 10x + 2 ← is in standard form
with a = 1 and b = - 10, thus
[tex]x_{vertex}[/tex] = - [tex]\frac{-10}{2}[/tex] = 5
Substitute x = 5 into g(x) for the corresponding y- coordinate
g(5) = 5² - 10(5) + 2 = 25 - 50 + 2 = - 23
vertex = (5, - 23)
Thus the translation from (0, 0 ) → (5, - 23) is
< 5, - 23 >
