Answer:
The horizontal component is 96.42 N
The vertical component is 114.91 N
Explanation:
A force 150 newtons is inclined at 50 degrees to the horizontal direction
We need to find its component in the horizontal and vertical directions
[tex]F_{x}[/tex] is the horizontal component
[tex]F_{y}[/tex] is the vertical component
Look to the attached figure:
The horizontal component [tex]F_{x}[/tex] is the product of F and cosine
the angle between F and the horizontal
The vertical component [tex]F_{y}[/tex] is the product of F and sine
the angle between F and the horizontal
→ [tex]F_{x}[/tex] = F cos(50)
→ [tex]F_{x}[/tex] = 150 cos(50)
→ [tex]F_{x}[/tex] = 96.42 N
→ [tex]F_{y}[/tex] = F sin(50)
→ [tex]F_{y}[/tex] = 150 sin(50)
→ [tex]F_{y}[/tex] = 114.91 N
The horizontal component is 96.42 N
The vertical component is 114.91 N
