Answer:
Part a) [tex]y=35x+115[/tex]
Part b) [tex]\$1,165[/tex]
Step-by-step explanation:
Part a)
Let
x -----> the number of weeks
y ----> the total amount Chem has deposited in a saving account
we know that
The equation of a line in slope intercept form is
[tex]y=mx+b[/tex]
where
m is the rate or slope of the linear equation
b is the y-intercept of the linear equation or initial value (value of y when the value of x is equal to zero)
In this problem we have that
The rate or slope is equal to
[tex]m=35\frac{\$}{week}[/tex] -----> amount deposited by Chem each week
The y-intercept or initial value is
[tex]b=\$115[/tex] ----> amount deposited originally in the saving account
substitute the values
[tex]y=35x+115[/tex]
Part b) How much has Chem deposited 30 weeks after his initial deposit?
For x=30 weeks
substitute in the equation
[tex]y=35(30)+115[/tex]
[tex]y=\$1,165[/tex]
