Answer:
The dimensions of triangle are 66 ft, 33 ft and 47 ft
Step-by-step explanation:
Let
x -----> the length of one side
y -----> the length of the shortest side
z -----> the length of the third side
we know that
The perimeter of triangle is
[tex]P=x+y+z[/tex]
[tex]P=146\ ft[/tex]
so
[tex]146=x+y+z[/tex] -----> equation A
[tex]x=2y[/tex] -----> equation B
[tex]z=y+14[/tex] ----> equation C
Substitute equation B and C in equation A and solve for y
[tex]146=2y+y+y+14[/tex]
[tex]146=4y+14[/tex]
[tex]4y=146-14[/tex]
[tex]4y=132[/tex]
[tex]y=33\ ft[/tex]
Find the value of x
[tex]x=2(33)=66\ ft[/tex]
Find the value of z
[tex]z=33+14=47\ ft[/tex]
therefore
The dimensions of triangle are 66 ft, 33 ft and 47 ft