Answer:
The answer to your question is: 3305.6 g of HNO₃
Explanation:
Data
mass HNO₃ = ?
mass NH₃ = 892 g
Balanced Reaction
2 NH₃ + 4 O₂ ⇒ 2HNO₃ + 2H₂O
MW NH₃ = 14 + 3 = 17g
MW HNO₃ = 1 + 14 + 48 = 63 g
34 g of NH₃ ------------------ 126 g of HNO₃
892 g of NH₃ ------------------ x
x = (892 x 126) / 34
x = 3305.6 g of HNO₃