Answer:
The answer to your question is: Volume = 0.117 l
Explanation:
Data
V = ?
M = 9 x 10 ⁻²
mass = 1,9 g of KH₂AsO₄
MW KH₂AsO₄ = 39 + 2 + 75 + 64 = 180 g
Process
180 g of KH₂AsO₄ ------------------ 1 mol
1.9 g ------------------ x
x = 0.0011 mol of KH₂AsO₄
Molarity = # of moles / volume
Volume = # of moles / molarity
Volume = 0.0011 mol of KH₂AsO₄ / 0.09
Volume = 0.117 l = 117 ml
