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Complete and balance the molecular equation for the reaction of aqueous ammonium bromide, NH4Br,
and aqueous lead(II) acetate, Pb(C2H3O2)2. Include physical states.

Complete and balance the molecular equation for the reaction of aqueous ammonium bromide NH4Br and aqueous leadII acetate PbC2H3O22 Include physical states class=

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Answer:

Molecular equation:

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)

Explanation:

  • The molecular equation of the reaction between aqueous ammonium bromide and aqueous lead (ii) acetate is given by;

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)

  • This is an example of a double displacement reaction where two ionic compounds exchange ions with each other to form two new compounds or salts.
  • It can also be a precipitation reaction due to the formation of precipitate from two ionic compounds. Lead(ii) bromide is the precipitate formed during the reaction.
  • The net ionic equation for the reaction is;

2Br⁻(aq) + Pb²⁺(aq)→ PbBr₂(s)