ANSWER:
The slope of the given line [tex]y+2=\frac{3}{4}(x-5)[/tex] is [tex]m = \frac{3}{4}[/tex] and point on the given line is (5, -2).
SOLUTION:
From question, given equation = y+2= [tex]\frac{3}{4}(x-5)[/tex] --- eqn (1)
We need to find the slope of the given line and a point through which the given line passes.
Given equation is in the form of Point – Slope form. The point slope form is given as
[tex]\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)[/tex] ---- eqn (2)
Where (x , y) are equation variables,
[tex]\left({x}_{1}, \mathrm{y}_{1}\right)[/tex] are coordinates of the given point.
m = slope of given line.
On comparing the both equations (1) and (2) we get the values of slope and point through which the line passes.
[tex]y_{1} = -2[/tex]
[tex]m=\frac{3}{4}[/tex]
[tex]x_{1} =5[/tex]
Hence slope of the given line is [tex]m = \frac{3}{4}[/tex] and point on the given line is (5, -2).
