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A ball is thrown horizontally from the top of
a building 140 m high. The ball strikes the
ground 75 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s.

Respuesta :

Answer:

52.38 m/s

Explanation:

AL2006

Answer:

54.23 m/s

Explanation:

-- time to fall from 140m = 5.35 s

-- vertical speed after 5.35 s =

Speed = (5.35) x (9.8) = 52.38 m/s

-- horizontal speed = (75m/5.35s)

Speed = 14.03 m/s

Resultant speed due to vertical & horizontal speed components:

Speed = sqrt(52.38^2 + 14.03^2)

Speed = 54.23 m/s

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