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Consider the reaction C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l) in which 10.5 g of sucrose, C12H22O11, was burned in a bomb calorimeter with a heat capacity of 7.50 kJ/oC (including its water). The temperature inside the calorimeter was found to increase by 20.2 oC. Based on this information, what is the heat of this reaction per mole of sucrose?

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jufsanabriasa

Answer:

The heat of reaction is 4938 kJ/mole

Explanation:

It is possible to calculate the heat of a reaction using:

[tex]q = SpecificHeat *dT[/tex]

For the reaction:

C₁₂H₂₂O₁₁ (s) + 12 O₂ (g) → 12 CO₂ (g) + 11 H₂O (l)

Specific heat: 7,50kJ/°C

dT = 20,2°C

Thus, q = 151,5 kJ

The moles of sucrose are: 10,5g /342,2965 g/mol = 0,030675 moles

The heat of reacton is:

[tex]\frac{151,5 kJ}{0,030675moles} = 4938 kJ/mol[/tex]

I hope it helps!

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