Answer:
a) P(x>8) = 0.3937
b) P(x = 2) =0.04661
Step-by-step explanation:
a) From to find the probabilty that in this specific time period, more than 8 cars arrive at the intesection, we use the probability function thus
P(x>8) = 1 - P(x≤8), Cause you can use the complement for calculate this probability , then:
P(x≤8) = [tex]\frac{e^{-6}*6^{0} }{0!}+\frac{e^{-6}*6^{1} }{1!}+\frac{e^{-6}*6^{2} }{2!}+...[/tex] , until x= 8, then you obtain:
P(x≤8)=0.6063 and
P(x>8) = 1 - P(x≤8)= 1-0.6063 = 0.3937
b) P(x=2)= [tex]\frac{e^{-6}*6^{2} }{2!}[/tex]
P(x = 2) =0.04661
