Respuesta :
Answer:
averaage speed is v = 13 feet / s
Explanation:
The average speed is the ratio of the distance traveled in a given time interval, let's calculate the distance that the body travels in the two instants of time that give us
t = 1 s
d (1) = 2.6667 1²
d (1) = 2.6667 feet
t = 4 s
d (4) = 2.6667 4²
d (4) = 42.6672 feet
Let's calculate the speed
v = Δx / Δt
v = (42.6672 -2.6667) / (4-1)
v = 40/3
v = 13.33335 feet / s
v = 13 feet / s
The average speed of the object is the ratio of the difference of distance covered by object for 1 and 4 seconds and the difference in the time interval.
The average speed of the object is 13.3335 feet per second.
What is an average speed?
The average speed of an object can be defined as the total distance covered by the object in a given time interval.
Given that the distance of the object is expressed by the function,
[tex]d(t)= 2.6667 t^2[/tex]
For t = 1 second, the distance will be,
[tex]d(t)= 2.6667\times 1^2[/tex]
[tex]d(t)= 2.6667\;\rm Feet[/tex]
For t = 4 seconds, the distance will be,
[tex]d(t)= 2.6667\times 4^2[/tex]
[tex]d(t)=42.6672 \;\rm Feet[/tex]
The average velocity of the object for the time interval of 1 to 4 seconds is given as,
[tex]v = \dfrac {\Delta d}{\Delta t}[/tex]
[tex]v = \dfrac { 42.6672- 2.6667}{4-1}[/tex]
[tex]v = 13.3335\;\rm Feet/second[/tex]
Hence we can conclude that the average speed of the object is 13.3335 feet per second.
To know about the speed, follow the link given below.
https://brainly.com/question/5794232.
