Explanation:
The given data is as follows.
Initial atmospheric pressure of the O = 760 torr
The partial pressure of [tex]O_{2}[/tex] = [tex]760 torr \times \frac{22}{100}[/tex]
= 167.2 torr
Partial pressure of oxygen ([tex]O_{2}[/tex]) in the blood is 20 torr.
Therefore, calculate the carrying capacity as follows.
Carrying capacity = [tex]\frac{(167.2 torr - 20 torr) - (75 torr - 20 torr)}{(167.2 torr - 20 torr)} \times 100[/tex]
= [tex]\frac{147.2 torr - 55 torr}{147.2 torr}\times 100[/tex]
= 0.6263
or, = 62.6%
Thus, we can conclude that the oxygen carrying capacity is 62.6%.
