Respuesta :
Explanation:
Given that,
Height = 3.40 m
Speed of water = 9.32 m/s
Angle = 80.0°
Suppose the angle at diving board is 10°.
(a). We need to calculate the magnitude of his initial velocity
Using the formula of horizontal velocity
[tex]u\cos\theta=u\cos\theta[/tex]
[tex]u=\dfrac{u\cos\theta}{u}[/tex]
Put the value into the formula
[tex]u=\dfrac{9.32\cos80}{\cos10}[/tex]
[tex]u=1.64\ m/s[/tex]
(b). We need to calculate the direction of his initial velocity,
The direction of his initial velocity is 10° east of south.
(c). We need to calculate the time
Using formula of time
[tex]t=\dfrac{u\sin\theta}{g}[/tex]
Put the value into the formula
[tex]t=\dfrac{1.64\sin10}{9.8}[/tex]
[tex]t=0.029\ sec[/tex]
We need to calculate his maximum height above the water
Using equation of motion
[tex]S_{y}=u_{y}+\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]S_{y}=1.64\sin10+\dfrac{1}{2}\times9.8\times(0.029)^2[/tex]
[tex]S_{y}=0.288\ m[/tex]
Hence, This is the required solution.
