Propane can be turned into hydrogen by the two-step reforming process. In the first step, propane and water react to form carbon monoxide and hydrogen: C3H8(g)+3H2O(g)→3CO(g)+7H2(g) In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide: CO(g)+H2O(g)→H2(g)+CO2(g) Write the net chemical equation for the production of hydrogen from propane and water. Be sure your equation is balanced.

Respuesta :

Answer:

The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)

Explanation:

First equation:

The reactants propane and water  react to form the products CO and H2

C3H8(g) + 3H2O(g) → 3CO(g) + 7H2(g)

Second equation:

The products CO and H2 will react

CO(g) + H2O(g) → H2(g) + CO2(g)

We should multiply the equation by 3 (to equal the products of the first equation)

3CO(g) + 3H2O(g) → 3H2(g) + 3CO2(g)

Add the second to the first equation:

C3H8(g) + 3 H2O(g) + 3 CO(g) + 3 H2O(g) → 3 H2(g) + 3CO2(g) + 3 CO(g) + 7 H2(g)

The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)

Oseni

The net chemical equation would be the addition of the steps.

Net chemical equations

The equation of the first step in the reaction is;  

C3H8(g)+3H2O(g)→3CO(g)+7H2(g)

While that of the second step is:

CO(g)+H2O(g)→H2(g)+CO2(g)

Adding the two equations together and canceling out the entities that appear on both sides:

C3H8(g)+3H2O(g)→3CO(g)+7H2(g)

CO(g)+H2O(g)→H2(g)+CO2(g)

C3H8(g) + 4H2O(g) --> 2CO(g) + 8H2(g) + CO2(g)

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