Answer:
R = 33.1 m and y = 8.27 m
Explanation:
This exercise is projectile launch, let's use the scope equation to find the displacement on the X axis
R = vo2 sin 2θ / g
R = 18 2 sin (2 45) /9.8
R = 33.1 m
First let's look for the velocity components
vox = vo cos θ
voy = vo sin θ
vox = 18 cos 45
vox = 12.73 m / s
voy = 18 sin 45
voy = 12.73 m / s
To find the maximum vertical displacement, where the vertical velocity must be zero, we can use the equation
[tex]v_{fy}[/tex]² = [tex]v_{oy}[/tex]² - 2 g y
0 = [tex]v_{oy}[/tex]² - 2 g y
y =[tex]v_{oy}[/tex]² / 2g
y = 12.73² / (2 9.8)
y = 8.27 m
