Respuesta :
Answer:
33.79°C
Explanation:
HCl and NaOH completely neutralize because they are strong acid and base.
In 100 mL of HCl we have 0.102 moles and in 50mL of NaOH we have 0.102 moles
As everything reacts, we have 0.102 moles of H2O.
The enthalpy of neutralization of 1 mole is -57kJ, to 0,102 moles is -5.814 kJ. The reaction is exothermic.
Now, we have a 150 mL sample, as the density is 1.00 g/ml, we have 150 g of solution, with the specific heat of 4.184 J/g°C.
With the equation Q = mcΔT, as Q is the heat (5,817 J), m is the mass (150 g) c is the specific heat (4.184 J/g°C) and ΔT is the temperature variation.
5,814 = 150 x 4.184 x ΔT
ΔT= 9.26 °C
T = Ti + ΔT = 24.53 + 9.26 = 33.79 °C
The study of chemicals and bonds is called chemistry. When the amount of product and reactant get equal then is said to be equilibrium.
The correct answer is 33.79°C
What is specific heat?
- The specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample. Specific heat is also sometimes referred to as massic heat capacity.
HCl and NaOH completely neutralize because they are strong acid and base. In 100 mL of HCl, we have 0.102 moles and in 50mL of NaOH we have 0.102 moles
As everything reacts, we have 0.102 moles of H2O. The enthalpy of neutralization of 1 mole is -57kJ, to 0,102 moles is -5.814 kJ. The reaction is exothermic.
Now, we have a 150 mL sample, as the density is 1.00 g/ml, we have 150 g of solution, with the specific heat of 4.184 J/g°C.
Q = mcΔT, where,
- Q is the heat (5,817 J),
- m is the mass (150 g)
- C is the specific heat (4.184 J/g°C)
- ΔT is the temperature variation.
Place all the values in the equation.
[tex]5,814 = 150 * 4.184 * T[/tex]
ΔT= 9.26 °C
T = Ti + ΔT = 24.53 + 9.26 = 33.79 °C
Hence, the correct answer is 33.79.
For more information about the question, refer to the link:-
https://brainly.com/question/16759172
