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An airplane maintains a speed of 585 km/h relative to the air it is flying through as it makes a trip to a city 815 km away to the north. (a) What time interval is required for the trip if the plane flies through a headwind blowing at 32.1 km/h toward the south? 1.47 Correct: Your answer is correct. h (b) What time interval is required if there is a tailwind with the same speed?

Respuesta :

Answer:

a)   t = 1.47 h    b) t = 1.32 h

Explanation:

a)  In this problem the plane and the wind are in the same North-South direction, whereby the vector sum is reduced to the scalar sum (ordinary). Let's calculate the total speed

     v = [tex]v_{f}[/tex]f - [tex]v_{w}[/tex]

     v = 585 -32.1

     v = 552.9 km / h

We use the speed ratio in uniform motion

     v = x / t

     t = x / v

     t = 815 /552.9

     t = 1.47 h

b)  We repeat the calculation, but this time the wind is going in the direction of the plane

      v=  [tex]v_{f}[/tex]f - [tex]v_{w}[/tex]

      v 585 + 32.1

      v = 617.1 km / h

      t = 815 /617.1

      t = 1.32 h

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