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You cause a particle to move from point A, where the electric potential is 11.3 V, to point B, where the electric potential is −25.9 V. Calculate the change that occurs in the particle's electrostatic potential energy, when the particle is an electron, a proton, a neutral hydrogen atom, and a singly ionized helium atom (i.e., lacking one electron from its neutral state).

Respuesta :

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Explanation:

The electric potential is the electric potential energy per unit of charge

[tex]V=\frac{U}{q}[/tex]

Using this definition, we can calculate the electrostatic potential energy change between point A and B:

[tex]\Delta U=U_A-U_B\\\Delta U=qV_A-qV_B\\\Delta U=q(V_A-V_B)[/tex]

Electron: [tex]q=-1.6*10^{-19}C[/tex]

[tex]\Delta U=-1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=-5.952*10^{-18}J[/tex]

Proton: [tex]q=1.6*10^{-19}C[/tex]

[tex]\Delta U=1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=5.952*10^{-18}J[/tex]

Neutral hydrogen atom: [tex]q=0[/tex]

[tex]\Delta U=0[/tex]

Singly ionized helium atom: [tex]q=1.6*10^{-19}C[/tex]

[tex]\Delta U=1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=5.952*10^{-18}J[/tex]

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