Answer:
The power output of the oscillator is 0.350 watt.
Explanation:
Given that,
Diameter = 1.0 mm
Tension = 5.7 N
Frequency = 57.0 Hz
Amplitude = 0.54 cm
We need to calculate the power output of the oscillator
Using formula of the power
[tex]P=\dfrac{1}{2}\times\mu\times\omega^2\times a^2\times v[/tex]
Put the value into the formula
[tex]P=\dfrac{1}{2}\times A\times\rho\times\omega^2\times a^2\times\dfrac{\sqrt{T}}{\mu}[/tex]
[tex]P=\dfrac{1}{2}\times3.14\times(0.0005)^2\times7850\times(2\times\pi\times57.0)^2\times(0.54\times10^{-2})^2\times\sqrt{\dfrac{5.7}{3.14\times(0.0005)^2\times7850}}[/tex]
[tex]P=0.350\ Watt[/tex]
Hence, The power output of the oscillator is 0.350 watt.
