You do an experiment in which you need 0.5 mole of tyrosine (C9H11NO3) .

How many grams must you weigh out?


65 g


90.5 g


181 g


272 g

Respuesta :

Answer:

90.5 g

Explanation:

we know 1 mole of thyrosine = 181g

so 0.5 mole thyrosine =181*0.5

                                      =90.5g

Answer: Option (b) is the correct answer.

Explanation:

Number of moles given are 0.5 mol and molar mass of tyrosine ([tex]C_{9}H_{11}NO_{3}[/tex]) is 181.19 g/mol.

Therefore, calculate the mass of given molecules follows.

   No. of moles of tyrosine = [tex]\frac{mass}{\text{molar mass}}[/tex]

                              0.5 mol = [tex]\frac{mass}{181.19 g/mol}[/tex]

                           mass = 90.595 g

Therefore, we can conclude that mass of 0.5 mole of tyrosine ([tex]C_{9}H_{11}NO_{3}[/tex]) is 90.5 g.