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Automobile airbags inflate due to the formation of nitrogen gas from the chemical reaction 2NaN3(s)⟶3N2(g)+2Na(s) Identify the number of each atom in the reactants and products for this balanced reaction. Identify the number of Na atoms in the reactants and products.

Respuesta :

mixter17

First part:

2 atoms of Na

6 atoms of N

Second part:

2 atoms of N

2 atoms of Na

Why?

We are given the chemical reaction, so, we can extract the number of atoms for both reactants and products.

We are given the chemical equation:

[tex]2NaN_{3}=3N_{2}+2Na[/tex]

We can rewrite it as follow:

[tex]2(NaN_{3})=3N_{2}+2Na[/tex]

From the reactants, we have:

[tex]2(NaN_{3})[/tex]

[tex]2Na=2atoms\\2N_{3}=2*3=6atoms[/tex]

From the products we have:

[tex]3N_{2}+2Na[/tex]

[tex]3N_{2}=3*2=6atoms[/tex]

[tex]2Na=2atoms[/tex]

Hence, we have that:

There are 6 atoms of N in the reactants and 6 atoms of N in the products.

and

There are 2 atoms of Na in the reactants and 2 atoms of Na in the products since we have a balanced equation.

Have a nice day!

fichoh

The Left and right hand side of a chemical equation denotes the reactant and product side respectively. Hence, the number of Na atoms in the reactant and product side is 2 atoms respectively.

Given the equation :

  • [tex] 2NaN_{3}(s)⟶3N_{2}(g)+2Na(s) [/tex]

Product side :

  • [tex] 2NaN_{3}(s)[/tex]

Na atoms = 2 atoms

Nitrogen atoms = 2 × 3 = 6 atoms

Reactant side :

  • [tex] 3N_{2}(g)+2Na(s) [/tex]

Na = 2 atoms

Nitrogen, N atoms = (3 × 2) = 6 atoms

Therefore, the Number of Na atoms in the reactant and product side is 2 atoms.

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