11. You have two specimens both of which are cylindrical with a diameter of 20 mm and a length of 200 mm. One is made of a titanium alloy (E = 100 GPa) and the other is made out of stainless steel (E = 200 GPa). Both of them are subjected to a tensile force of 500 N. Which of them will have higher stress? Which will develop higher strain? If possible, can you determine which of the specimens will be stronger?

Respuesta :

Answer:

Stress will be same for both specimen.

Titanium alloy have more strain as compare to stainless steel.

Stainless steel is more stronger as compare to titanium alloy.

Explanation:

Given that

d = 20 mm

L= 200 mm

P= 500 N

Specimen 1(titanium alloy):

E = 100 GPa

Specimen 2(Stainless steel):

E = 200 GPa

Stress given as

[tex]\sigma  =\dfrac{P}{A}[/tex]

P=Load

A= Cross sectional area

[tex]A=\dfrac{\pi d^2}{4}[/tex]

[tex]A=\dfrac{\pi \times 20^2}{4}\ mm^2[/tex]

[tex]A=314.15\ mm^2[/tex]

[tex]\sigma  =\dfrac{500}{314.15}\ MPa[/tex]

σ = 1.59 MPa

Both the specimen have same force and same dimensions so the stress will be same for both specimen.

We know that

σ =  ε .E

σ= stress

ε = strain

E= Modulus of elasticity

Specimen 1(titanium alloy):

E = 100 GPa

σ =  ε .E

1.59 = 100 x 1000 x ε                       ( 1 GPa = 1000 MPa)

[tex]\varepsilon =1.59\times 10^{-5}[/tex]  ------1

Specimen 2(Stainless steel):

E = 200 GPa

σ =  ε .E

1.59 = 200 x 1000 x ε                    

[tex]\varepsilon =0.795\times 10^{-5}[/tex] -----------2

From equation 1 and 2

So we can say that titanium alloy have more strain as compare to stainless steel.

E for  stainless steel= 200 GPa

E for   titanium alloy = 200 GPa

E stainless steel is more then titanium alloy that is why stainless steel is more stronger .