Answer:
12500 V
Explanation:
The electric field in the gap of a parallel-plate capacitor is uniform, so the following relationship between electric field strength, potential difference and distance can be used:
[tex]\Delta V = E d[/tex]
where
[tex]\Delta V[/tex] is the potential difference between the plates
E is the electric field strength
d is the distance between the plates
For the capacitor in this problem, we have
[tex]E=5.00\cdot 10^6 V/m[/tex]
[tex]d = 2.50 mm = 2.50\cdot 10^{-3} m[/tex]
Substituting, we find
[tex]\Delta V = (5.00\cdot 10^6)(2.50\cdot 10^{-3})=12500 V[/tex]
