Respuesta :
Answer:
Distance, r = 3721.04 meters
Explanation:
It is given that,
Charges on both humans, [tex]q_1=q_2=1\ C[/tex]
Electric force of attraction between them, F = 650 N
We need to find the separation between two humans. It can be solved using the following formula as :
[tex]F=\dfrac{kq^2}{r^2}[/tex]
[tex]r=\sqrt{\dfrac{kq^2}{F}}[/tex]
[tex]r=\sqrt{\dfrac{9\times 10^9\times (1)^2}{650}}[/tex]
r = 3721.04 meters
So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.
Force on the particle is defined as the application of the force field of one particle on another particle. The distance between the humans carrying charge particles will be 3721.04 meters.
What is electric force?
Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force. it is the ratio of voltage to the distance between them.
The given data in the problem;
[tex]F_E[/tex] is the electric force =650 N
q is the charge = 1.0 C
r is the distance between the humans carrying charge particle
Mathematically electric force between the two charges is given by ;
[tex]\rm F_E=\frac{Kq^{2} }{r^2} \\\\\rm r^2 =\frac{Kq^{2} }{F_E} \\\\r=\sqrt{\frac{Kq^{2} }{F_E} } \\\\r=\sqrt{\frac{9\times10^9(1)^{2} }{650} } \\\\\rm r=3721.04 m.[/tex]
Hence the distance between humans is 3721.04 meters.
To learn more about the electric force refer to the link;
https://brainly.com/question/1076352
