A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.
(a) Neglecting air resistance, find the shell's horizontal range. 280,000 Correct: Your answer is correct. m
(b) Find the amount of time the shell is in motion.?

Respuesta :

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

[tex]v = 1.74 x 10^{3}  ( \frac{m}{s} )[/tex]

[tex]\alpha = 58[/tex]°

[tex]v_{y} =v*Sen (\alpha )\\v_{x} =v*Cos (\alpha )[/tex]

[tex]v_{y} =1740*Sen (58 )\\v_{x} =1740*Cos (58)[/tex]

[tex]v_{y} = 1475.603 \frac{m}{s}\\v_{x} = 922.059 \frac{m}{s}\\[/tex]

[tex]t= \frac{2*v_{y} }{g}[/tex]

[tex]t= \frac{2*1475.603 }{9.8}[/tex]

[tex]t= 301.143 s[/tex]

[tex]v= \frac{s}{t} \\s= v_{x}*t[/tex]

[tex]s= 922.059 \frac{m}{s} * 301.143 s[/tex]

[tex]s = 277671.77 m[/tex]