For this case we have to by definition:
[tex]d = \frac {M} {V}[/tex]
Where:
d: It is the density
M: It's the mass
V: It is the volume
According to the data we have to:
[tex]d = 3.0 \frac {g} {cm ^ 3}[/tex]
On the other hand we have that 1 meter is equivalent to 100 centimeters. Thus the measurements of the walkway are:
600 cm long, 100 cm wide and 10 cm thick. Looking for the volume we have:
[tex]V = 600 * 100 * 10\\V = 600,000 cm ^ 3[/tex]
According to the formula we have:
[tex]M = d * V\\M = 3.0 \frac {g} {cm ^ 3} * 600,000 cm ^ 3\\M = 1,800,000g[/tex]
Thus, the mass of the walkway is 1,800,000g
Answer:
1,800,000g
