Answer:
0,1 mol of carbon and 0.2 moles of hydrogen were in the original sample.
Explanation:
The combustion reaction of the compound is
[tex]C_{x} H_{y} O_{z} +O_{2} -> CO_{2} + H_{2}O[/tex]
And the molar mass of CO2 and H2O are 44g/mol and 18g/mol respectively
All the mass of carbon producing the CO2 must come from the carbon of the unknown compound, thus it is necessary to calculate the moles of carbon in 4.4g of CO2
[tex]\frac{4.4gx12g}{44gx12g/mol} = 0.1 mol[/tex] of Carbon
Also, all the mass of hydrogen producing the H2O must come from the hydrogen of the unknown compound, hence it is necessary to calculate the moles of hydrogen in 1.8g of water
[tex]\frac{1.8gx2g}{18gx1g/mol} = 0.2 mol[/tex] of Hydrogen