Answer:25 N
Explanation:
Given
mass of 5 , 3 & 2 kg blocks lie on floor
Force on 50 N pushes the 5 kg box
[tex]Let N_1[/tex] be the reaction on 2 kg box therefore
[tex]N_1=2\times a[/tex]
where a is the acceleration of the system
[tex]N_2=[/tex]reaction on 3 kg block by 5 kg block
[tex]N_2-N_1=3a[/tex]
[tex]N_2=5a[/tex]
Now for 5 kg block
[tex]F-N_2=5a[/tex]
F=10a
[tex]a=\frac{F}{10}=5 m/s^2[/tex]
Force exerted by 5 kg block on 3 kg block is
[tex]N_2=5\times 5=25 N[/tex]
