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Suppose the time it takes for a purchasing agent to complete an online ordering process is normally distributed with a mean of 8 minutes and a standard deviation of 2 minutes. Suppose a random sample of 25 ordering processes is selected. What is the standard deviation of the sampling distribution of mean​ times? (Round to one decimal place.)

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JeanaShupp

Answer:  0.4

Step-by-step explanation:

We know that the standard deviation of the sampling distribution of mean​ is given by:-

[tex]\sigma_x=\dfrac{\sigma}{\sqrt{n}}[/tex]

Given : Standard deviation : [tex]\sigma= 2\text{ minutes}[/tex]

Sample size : n= 25

Then, the standard deviation of the sampling distribution of mean​ times will be :-

[tex]\sigma_x=\dfrac{2}{\sqrt{25}}\\\\\Rightarrow\ \sigma_x=\dfrac{2}{5}=0.4[/tex]

Hence, the standard deviation of the sampling distribution of mean​ times=0.4

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