Answer:
Stress will be same for both specimen.
Titanium alloy have more strain as compare to stainless steel.
Stainless steel is more stronger .
Explanation:
d = 20 mm
L= 200 mm
P= 500 N
Specimen 1:
E = 100 GPa
Specimen 2:
E = 200 GPa
We know that stress given as
[tex]\sigma =\dfrac{P}{A}[/tex]
[tex]A=\dfrac{\pi d^2}{4}[/tex]
[tex]A=\dfrac{\pi \times 20^2}{4}\ mm^2[/tex]
[tex]A=314.15\ mm^2[/tex]
[tex]\sigma =\dfrac{500}{314.15}\ MPa[/tex]
σ = 1.59 MPa
Both specimen have same force and same dimensions so the stress will be same for both specimen.
We know that with in the elastic limit
σ = ε .E
E= Modulus of elasticity
σ= stress
ε = strain
Specimen 1:
E = 100 GPa
σ = ε .E
1.59 = 100 x 1000 x ε ( 1 GPa = 1000 MPa)
[tex]\varepsilon =1.59\times 10^{-5}[/tex]
Specimen 2:
E = 200 GPa
σ = ε .E
1.59 = 200 x 1000 x ε ( 1 GPa = 1000 MPa)
[tex]\varepsilon =0.795\times 10^{-5}[/tex]
[tex]\varepsilon_1 =1.59\times 10^{-5}[/tex]
[tex]\varepsilon_2 =0.795\times 10^{-5}[/tex]
So we can say that titanium alloy have more strain as compare to stainless steel.
E stainless steel is more then titanium alloy that is why stainless steel is more stronger .
