Answer
given,
head gradient = 0.05
hydraulic conductivity = 1 m/d
effective porosity = 0.2
from Darcy's law
V = k i
v = 1 × 0.05
= 0.05 m/day
seepage velocity
[tex]v_s = \dfrac{v}{n}[/tex]
[tex]v_s = \dfrac{0.05}{0.2}[/tex]
[tex]v_s = 0.25 m/day[/tex]
specific discharge
[tex]q = \dfrac{Q}{A}= k\dfrac{dh}{dl}[/tex]
q = 1 × 0.05
q = 0.05 m/day
b) Q = A V
=20 × 850 × 0.05
Q = 850 m³/day
c) time require to move 75 m
[tex]t = \dfrac{75}{v_s}[/tex]
[tex]t = \dfrac{75}{0.25}[/tex]
t = 300 days
