Answer:
Acceleration of the car will be [tex]a=0.1375m/sec^2[/tex]
Explanation:
We have given mass of the ball m = 1600 kg
Force in north direction F= 7560 N
Resistance force which opposes the movement of car [tex]F_R=7340N[/tex]
So net force on the car [tex]F_{net}=F-F_R=7560-7340=220N[/tex]
According to second law of motion we know that F=ma
So [tex]220=1600\times a[/tex]
[tex]a=0.1375m/sec^2[/tex]
The acceleration of the car is 0.138 m/s²
The given parameters;
mass of the car, m = 1600 kg
applied force, F = 7560 N due north
resistance of the mud and car combined = 7340 N due south
The resultant of the upward force is calculated as;
F = F(north) - F(south)
F = 7560 N - 7340 N
F = 220 N
The acceleration of the car is determined by applying Newton's second law of motion;
F = ma
where;
a is the acceleration of the car
[tex]a = \frac{F}{m} \\\\a = \frac{220}{1600} \\\\a = 0.138 \ m/s^2[/tex]
Thus, the acceleration of the car is 0.138 m/s²
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