Answer:
If the final question is; at what velocity will the first block start to move outward in m/s?
[tex]v = 3.5596 \frac{m}{s}[/tex]
Explanation:
The motion have the velocity that will make the block move using:
[tex]F_{1}*F_{r}+ F_{2}= Ec \\Ec= \frac{M*v^{2} }{r}[/tex]
[tex]m_{1} = 1.2 Kg[/tex]
[tex]m_{2} = 2.8 Kg[/tex]
[tex]r = 0,45 m[/tex]
μ[tex]s= 0,54[/tex]
Resolving:
[tex]\frac{m_{1}*v^{2} }{r} = us*m_{1}* g + m_{2} * g[/tex]
[tex]v^{2} = \frac{((us *m_{1} + m_{2})*g )* r}{m_{1} }[/tex]
[tex]v^{2} = \frac{((0.54 *1.2 + 2.8)*9.8 )* 0.45}{1.2}[/tex]
[tex]v^{2} = 12.6714 \frac{m^{2} }{s^{2} }[/tex]
[tex]v = 3.559 \frac{m}{s}[/tex]
