Answer:
The anchor point is 166.86 ft apart
Explanation:
The antenna and 2 wire from traingle ABC ( figure given below). we can immediately apply the law of sines
[tex]\frac{sinB}{b} = \frac{sinC}{c}[/tex]
[tex]sinC = \frac{c}{b} sin B = \frac{150}{170} sin 65 = 0.79[/tex]
there are two angles for which this happens c = 52.18 or c = 127.81 degree
But 127.81 + 65 > 180 so the only valid angle for c is 52.18 degree.
that mean A = 180 - B - C = 62.82 DEGREE
THUS required distance a is by the law of sines
[tex]\frac{sinA}{a} = \frac{sinB}{b}[/tex]
[tex]a = b \times [\frac {sinA}{sinB} = 166.86 ft [/tex]
