Answer:
A =$ 543,224.5
Step-by-step explanation:
Given,
plan to work for = 40 years
P = $3500 per month
APR = 6 % = [tex]\dfrac{0.06}{12}[/tex]
n= 12 × 25 = 300
[tex]A = \dfrac{P}{r}[1-(1+r)^{-n}][/tex]
[tex]A = \dfrac{3500}{\dfrac{0.06}{12}}[1-(1+\dfrac{0.06}{12})^{-300}][/tex]
A =$ 543,224.5
so, the deposits are required to achieve the desired monthly yield at retirement A =$ 543,224.5